Fundamental Theorem of Calculus (david.alvarezrosa.com)

43 points by dalvrosa 12 hours ago

47 comments:

by EdwardDiego an hour ago

> This post introduces the Riemann integral

Sweet! I'm keen to learn about the basic fundamentals of calculus!

> For each subinterval ...(bunch of cool maths rendering I can't copy and paste because it's all comes out newline delimited on my clipboard) ... and let m<sub>k</sub> and M<sub>k</sub> denote the infimum and supremum of f on that subinterval...

Okay, guess it wasn't the kind of introduction I had assumed/hoped.

Very cool maths rendering though.

As someone who never passed high school or got a degree thanks to untreated ADHD, if anyone knows of an introduction to the basic fundamentals of calculus that a motivated but under educated maths gronk can grok, I would gratefully appreciate a link or ten.

by ulrikrasmussen 9 minutes ago

3Blue1Brown has an excellent video series that introduces calculus using very intuitive animations and explanations: https://www.youtube.com/playlist?list=PLZHQObOWTQDMsr9K-rj53...

by chadcmulligan 16 minutes ago

If you dive into Analysis (the underlying theory behind calculus) this book - "How to Think About Analysis" by Lara Alcock is the book I wish I had when I studied it. Calculus by Spivak is the book I learnt from but it is probably not the easiest, it is very thorough though.

by mr_mitm an hour ago

Yeah, judging by the terseness, this is clearly aimed at undergrads. Then again, this is covered in literally every calculus class, so I'm not sure who this is supposed to be for.

by dalvrosa 38 minutes ago

Fair, sorry about that

by globalnode 26 minutes ago

Here's my understanding: 1: In the 'olden days' the area A(x) under the graph f(x) used to be approximated as a Riemann sum. 2: Using limits, as the delta x in the Riemann sum->0, we'd call that an integral and set it to be the exact area A(x). 3: If we then look at some small change in A(x), we might notice f(x) = A'(x)... mind blown. 4: since we can now say A is an anti-derivative of f, we have A(x)=F(x)+C (we have to add the C because the derivative of a constant is 0). 5: Using logic and geometry we have C=-F(a) which leads to... 6: The area under the graph f between [a,b] is A = F(b)-F(a). 7: We don't have to cry anymore about pages of Riemann sum calculations.

by homeonthemtn an hour ago
by UltraSane 40 minutes ago

I recommend Math Academy + Mathematica + YouTube + ChatGPT, Gemini, or Claude Opus and a LOT of motivation.

by Delphiza 43 minutes ago

https://minireference.com/

"The No Bullshit Guide to Math and Physics"

by moi2388 an hour ago

Khan academy

by mchinen 2 hours ago

I've studied the proofs before but there's still something mystical and unintuitive for me about the area under an entire curve being related to the derivative at only two points, especially for wobbly non monotonic functions.

I feel similar about the trace of a matrix being equal to the sum of eigenvalues.

Probably this means I should sit with it more until it is obvious, but I also kind of like this feeling.

by aquafox 14 minutes ago

If I tell you I have function f with f(a) = 10 and on it's path from a to b, the graph first increaes by 5 units then by another 10, and then later on drops by 25 units, you can immediately deduce that f(b) = f(a) + (+5 +10 -25) = 0. The fundamental theorem of calculus uses the same concept:

To see why \int_a^b f(x) dx = F(b) - F(a) with F'(x) = f(x),

we replace f with f' (and hence F with f) and get

\int_a^b f'(x) dx = f(b) - f(a).

Re-arranging terms, we get

f(b) = f(a) + \int_a^b f'(x) dx.

The last line just says: The value of function f at point b is is the value at point a plus the sum of all the infinitely many changes the function goes through on its path from a to b.

by ironSkillet 2 hours ago

It is not determined by the derivative, it's the antiderivative, as someone else mentioned. The derivative is the rate of change of a function. The "area under a curve" of the graph of a function measures how much the function is "accumulating", which is intuitively a sum of rates of change (taken to an infinitesimal limit).

by dalvrosa 36 minutes ago

Thanks for bringing some intuition!

by enriquto 36 minutes ago

> there's still something mystical and unintuitive for me about the area under an entire curve being related to the derivative

the discrete version is much clearer to me. Suppose you have a function f(n) defined at integer positions n. Its "derivative" is just the difference of consecutive values

     f'(n) = f(n+1) - f(n)
Then the fundamental theorem is just a telescopic sum:

     f(b) - f(a) = \sum_a^b f'(n)
by dalvrosa 5 minutes ago

Very. Very nice

by magicalhippo an hour ago

The antiderivative at x is defined as the area under the curve from 0 to x, which the Riemann sum gives a nice intuition for how you can get from the derivative.

So to get the area under the curve between a and b, you calculate the area under the curve from 0 to b (antiderivative at b) and subtract the area under the curve from 0 to a (antiderivative at a).

At least that's my sleep deprived take.

by 1980phipsi 35 minutes ago

I took calculus in high school and college, and I don't think any of my instructors explained the intuition as well. So sleep-deprived or not, it's a great one!

by dalvrosa 41 minutes ago

There is some geometric intuition in wikipedia page for this theorem you may like :)

by sambapa 2 hours ago

You meant antiderivative?

by emacdona 2 hours ago

> f is Riemann integrable iff it is bounded and continuous almost everywhere.

FWIW, I think this is the same as saying "iff it is bounded and has finite discontinuities". I like that characterization b/c it seems more precise than "almost everywhere", but I've heard both.

I mention that because when I read the first footnote, I thought this was a mistake:

> boundedness alone ensures the subinterval infima and suprema are finite.

But it wasn't. It does, in fact, insure that infima and suprema are finite. It just does NOT ensure that it is Riemann integrable (which, of course the last paragraph in the first section mentions).

Thanks for posting. This was a fun diversion down memory lane whilst having my morning coffee.

If anyone wants a rabbit hole to go down:

Think about why the Dirichlet function [1], which is bounded -- and therefore has upper and lower sums -- is not Riemann integrable (hint: its upper and lower sums don't converge. why?)

Then, if you want to keep going down the rabbit hole, learn how you _can_ integrate it (ie: how you _can_ assign a number to the area it bounds) [2]

[1] One of my favorite functions. It seems its purpose in life is to serve as a counter example. https://en.wikipedia.org/wiki/Dirichlet_function

[2] https://en.wikipedia.org/wiki/Lebesgue_integral

by mjdv 2 hours ago

> FWIW, I think this is the same as saying "iff it is bounded and has finite discontinuities".

It is not: for example, the piece-wise constant function f: [0,1] -> [0,1] which starts at f(0) = 0, stays constant until suddenly f(1/2) = 1, until f(3/4) = 0, until f(7/8) = 1, etc. is Riemann integrable.

"Continuous almost everywhere" means that the set of its discontinuities has Lebesgue measure 0. Many infinite sets have Lebesgue measure 0, including all countable sets.

by emacdona 2 hours ago

Ah, thanks for the clarification! Would it have been accurate then to have said:

"iff it is bounded and has countable discontinuities"?

Or, are there some uncountable sets which also have Lebesgue measure 0?

by jfarmer an hour ago

No, it's really sets of measure zero. The Cantor set is an example of an uncountable set of measure 0: https://en.wikipedia.org/wiki/Cantor_set

The indicator function of the Cantor set is Riemann integrable. Like you said, though, the Dirichlet function (which is the indicator function of the rationals) is not Riemann integrable.

The reason is because the Dirchlet function is discontinuous everywhere on [0,1], so the set of discontinuities has measure 1. The Cantor function is discontinuous only on the Cantor set.

Likewise, the indicator function of a "fat Cantor set" (a way of constructing a Cantor-like set w/ positive measure) is not Riemann integrable: https://en.wikipedia.org/wiki/Smith%E2%80%93Volterra%E2%80%9...

by ironSkillet an hour ago

No that's not true either. A quick Google will reveal many examples, in particular the "Cantor set".

by thaumasiotes an hour ago

The Cantor set is uncountable and has Lebesgue measure 0.

by dalvrosa 38 minutes ago

Great example

by jfarmer 2 hours ago

"Almost everywhere" means "everywhere except on a set of measure 0", in the Lebesgue measure sense.

Here's an example of a Riemann integrable function w/ infinitely many discontinuities: https://en.wikipedia.org/wiki/Thomae%27s_function

Anyone interested in this should check out the Prologue to Lebesgue's 1901 paper: http://scratchpost.dreamhosters.com/math/Lebesgue_Integral.p...

It gives several reasons why we "knew" the Riemann integral wasn't capturing the full notion of integral / antiderivative

by bandrami 2 hours ago

"Almost everywhere" is precisely defined, and it is broader than that. E.g. the real numbers are almost everywhere normal, but there are uncountably many non-normal numbers between any two normal reals.

by sambapa 2 hours ago

"almost everywhere" can mean the curve has countably infinite number of discontinuities

by Jaxan 2 hours ago

“Almost everywhere” is a mathematical term and can mean two things (I think):

- except finitely many, or

- except a set of measure zero.

by dalvrosa 39 minutes ago

Here is used in the Lebesgue measure theory sense

by bikrampanda 3 hours ago

What is the font used on the site?

by WCSTombs 36 minutes ago

Technically "it depends on the browser settings," but the body font Alegreya is served directly by the site, so I think it would be the one used in almost all cases.

The math fonts used in the formulas are just the ones provided by KaTeX, which I think are just TeX's default math fonts.

by viscousviolin 2 hours ago

Today I learned there's a CSS property for styling the first letter of a paragraph, neat. (https://css-tricks.com/almanac/properties/i/initial-letter/)

--edit: The font used for those initials is called Goudy Initialen: https://www.dafont.com/goudy-initialen.font

by quibono 7 minutes ago

I love this -- I'll have to do something like that for my site. I always liked the big initials on the start of a paragraph. Though it feels a bit more prose-applicable than for non-fiction writing.

by dalvrosa 40 minutes ago

Already replied :)

The source code of the website is open if you wanna check it out!

by crispyambulance 2 hours ago

That font, and how it's integrated with the math looks amazing. Katex for the math?

by viscousviolin 2 hours ago

Seems like Katex from the scripts getting loaded. I love the design too, kinda medieval-chic.

by eru 2 hours ago

Looks more early modern to me. :)

by emmelaich 2 hours ago
by genezeta 2 hours ago

Alegreya

by shmoil an hour ago

Good job, David. Have a lollipop. Now learn & write up the proof that the Henstock-Kurzweil integral integrates _every_ derivative. This is what we had in my calculus class on top of the outdated Riemann integral.

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